#### Question

If the polynomial equation \[a_0 x^n + a_{n - 1} x^{n - 1} + a_{n - 2} x^{n - 2} + . . . + a_2 x^2 + a_1 x + a_0 = 0\] n positive integer, has two different real roots α and β, then between α and β, the equation \[n \ a_n x^{n - 1} + \left( n - 1 \right) a_{n - 1} x^{n - 2} + . . . + a_1 = 0 \text { has }\].

(a) exactly one root

(b) almost one root

(c) at least one root

(d) no root

#### Solution

(c) at least one root

We observe that, \[n a_n x^{n - 1} + \left( n - 1 \right) a_{n - 1} x^{n - 2} + . . . + a_1 = 0\] is the derivative of the polynomial \[a_n x^n + a_{n - 1} x^{n - 1} + a_{n - 2} x^{n - 2} + . . . + a_2 x^2 + a_1 x + a_0 = 0\]

Polynomial function is continuous every where in *R* and consequently derivative in *R*

Therefore, \[a_n x^n + a_{n - 1} x^{n - 1} + a_{n - 2} x^{n - 2} + . . . + a_2 x^2 + a_1 x + a_0\] is continuous on

By algebraic interpretation of Rolle's theorem, we know that between any two roots of a function \[f\left( x \right)\] , there exists at least one root of its derivative.