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# Solution for F(X) = Sin 1 X for −1 ≤ X ≤ 1 Discuss the Applicability of Rolle'S Theorem for the Following Function on the Indicated Intervals ? - CBSE (Commerce) Class 12 - Mathematics

ConceptMaximum and Minimum Values of a Function in a Closed Interval

#### Question

f (x) = sin $\frac{1}{x}$ for −1 ≤ x ≤ 1 Discuss the applicability of Rolle's theorem for the following function on the indicated intervals ?

#### Solution

The given function is $f\left( x \right) = \sin\frac{1}{x}$ .

The domain of f is given to be $\left[ - 1, 1 \right]$ .

It is known that  $\lim_{x \to 0} \sin\frac{1}{x}$ does not exist.

Thus,  $f\left( x \right)$ is discontinuous at x = 0 on  $\left[ - 1, 1 \right]$ .

Hence, Rolle's theorem is not applicable for the given function.

Is there an error in this question or solution?

#### APPEARS IN

Solution for question: F(X) = Sin 1 X for −1 ≤ X ≤ 1 Discuss the Applicability of Rolle'S Theorem for the Following Function on the Indicated Intervals ? concept: Maximum and Minimum Values of a Function in a Closed Interval. For the courses CBSE (Commerce), CBSE (Arts), PUC Karnataka Science, CBSE (Science)
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