HSC Science (General) 12th Board ExamMaharashtra State Board
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Solution - Find (AB)-1 if A=[(1,2,3),(1,-2,-3)], B=[(1,-1),(1,2),(1,-2)] - HSC Science (General) 12th Board Exam - Mathematics and Statistics

Question

Find (AB)-1 if

`A=[(1,2,3),(1,-2,-3)], B=[(1,-1),(1,2),(1,-2)]`

 

Solution

`A=[(1,2,3),(1,-2,-3)], B=[(1,-1),(1,2),(1,-2)]`

`AB=[(1,2,3),(1,-2,-3)][(1,-1),(1,2),(1,-2)]`

= `[[6,-3],[-4,1]]`

`(AB)^-1(AB)=I`

`(AB)^-1[[6,-3],[-4,1]]=[[1,0],[0,1]]`

`"Using "R_1 -> 1/6R_1`

`(AB)^-1[[1,-1/2],[-4,1]]=[[1/6,0],[0,1]]`

`"Using " R_2 ->R_2+4R_1`

`(AB)^-1[[1,-1/2],[0,-1]]=[[1/6,0],[2/3,1]]`

`"using "R_2->(-1)R_2`

`(AB)^-1[[1,-1/2],[0,1]]=[[1/6,0],[-2/3,-1]]`

`"Using " R_1->R_1+(1/2)R_2`

`(AB)^-1[[1,0],[0,1]]=[[-1/6,-1/2],[-2/3,-1]]`

`(AB)^-1I=[[-1/6,-1/2],[-2/3,-1]]`

`(AB)^-1=[[-1/6,-1/2],[-2/3,-1]]`

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APPEARS IN

 2015-2016 (March) (with solutions)
Question 1.2.1 | 2 marks

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Solution for question: Find (AB)-1 if A=[(1,2,3),(1,-2,-3)], B=[(1,-1),(1,2),(1,-2)] concept: null - Inverse by Elementary Transformation. For the courses HSC Science (General) , HSC Science (Computer Science), HSC Science (Electronics), HSC Arts
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