#### Question

Inverse of the statement pattern (p ∨ q) → (p ∧ q) is

(A) (p ∧ q) → (p ∨ q)

(B) ∼ (p ∨ q) → (p ∧ q)

(C) (∼ p ∨ ∼ q) → (∼ p ∧ ∼ q)

(D) (∼ p ∧ ∼ q) → (∼ p ∨ ∼ q)

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#### Solution

(D) (∼ p ∧ ∼ q) → (∼ p ∨ ∼ q)

statement pattern: (p ∨ q ) → ( p ∧ q)

Its inverse is

~ (p ∨ q ) → ~ ( p ∧ q)

≡ (∼ p ∧ ∼ q) → (∼ p ∨ ∼ q)

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