CBSE Class 9CBSE
Share
Notifications

View all notifications

A Piece of Stone is Thrown Vertically Upwards. It Reaches the Maximum Height in 3 Seconds. If the Acceleration of the Stone Be 9.8 M/S2 Directed Towards the Ground - CBSE Class 9 - Science

Login
Create free account


      Forgot password?

Question

A piece of stone is thrown vertically upwards. It reaches the maximum height in 3 seconds. If the acceleration of the stone be 9.8 m/s2 directed towards the ground, calculate the initial velocity of the stone with which it is thrown upwards

Solution

v (final velocity) = 0 m/s
u (initial velocity) = ?
a (acceleration due to gravity i.e.,  g) = 9.8m/s2
t (time) = 3 sec
v  = u + gt
0 = u + 9.8 × 3
0 = u + 29.4
u  = −29.4m/s   
Note - Answer is in negative i.e. −29.4m/s, as it is directed opposite to the acceleration due to gravity and we have taken the motion along acceleration due to gravity as positive.
Answer: 29.4m/s

  Is there an error in this question or solution?

APPEARS IN

 Lakhmir Singh Solution for Science for Class 9 Part 1 Physics (2016 to Current)
Chapter 3: Gravitation
Short Answers | Q: 38 | Page no. 101

Video TutorialsVIEW ALL [1]

Solution A Piece of Stone is Thrown Vertically Upwards. It Reaches the Maximum Height in 3 Seconds. If the Acceleration of the Stone Be 9.8 M/S2 Directed Towards the Ground Concept: Mass and Weight.
S
View in app×