#### Question

A piece of stone is thrown vertically upwards. It reaches the maximum height in 3 seconds. If the acceleration of the stone be 9.8 m/s^{2} directed towards the ground, calculate the initial velocity of the stone with which it is thrown upwards

#### Solution

v (final velocity) = 0 m/s

u (initial velocity) = ?

a (acceleration due to gravity i.e., g) = 9.8m/s^{2}

t (time) = 3 sec**v = u + gt**

0 = u + 9.8 × 3

0 = u + 29.4

u = −29.4m/s **Note - Answer is in negative i.e. −29.4m/s, as it is directed opposite to the acceleration due to gravity and we have taken the motion along acceleration due to gravity as positive.**

Answer: 29.4m/s

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Solution A Piece of Stone is Thrown Vertically Upwards. It Reaches the Maximum Height in 3 Seconds. If the Acceleration of the Stone Be 9.8 M/S2 Directed Towards the Ground Concept: Mass and Weight.