#### Question

Assume that the mass of a nucleus is approximately given by M = Am_{p} where A is the mass number. Estimate the density of matter in kgm^{−3} inside a nucleus. What is the specific gravity of nuclear matter?

#### Solution

Given :-

Mass of the nucleus, M = Am_{p}

Volume of the nucleus, V = `4/3piR_0^3A`

Density of the matter, d = `M/V = (Am_p)/(4/3piR_0^3A)`

`= (3m_p)/(4 xx piR_0^3)`

`= (3 xx 1.007276)/(4 xx 3.14(1.1)^3)`

`= 3 xx 10^17 "kg/m"^3`

Specific gravity of the nuclear matter = `("Density of matter")/("Density of water")`

`therefore` Specific gravity = `(3 xx 10^17)/10^3 = 3 xx 10^14 "kg/m"^3`

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Solution Assume that the Mass of a Nucleus is Approximately Given by M = Amp Where a is the Mass Number. Estimate the Density of Matter in Kgm−3 Inside a Nucleus. Concept: Mass-energy and Nuclear Binding Energy - Mass - Energy.