# Mark the Correct Alternative in Each of the Following: the Sides of a Triangle Are 16 Cm, 30 Cm, 34 Cm. Its Area is - Mathematics

MCQ

Mark the correct alternative in each of the following:
The sides of a triangle are 16 cm, 30 cm, 34 cm. Its area is

#### Options

• 225 cm2

• 225  $\sqrt{3}$ cm2

• 225  $\sqrt{2}$ cm2

• 450 cm

• none above

#### Solution

The area of a triangle having sides aband s as semi-perimeter is given by,

A = sqrt( s(s-a)(s-b)(s-c)), where

s = ( a+b+c)/2

Therefore the area of a triangle say A, having sides 16 cm, 30 cm and 34 cm is given by

a = 16 cm ; b = 30 cm ; c = 34 cm

s =  (a+b+c)/2

s = (16 + 30 +34 )/2

s = 80/2

s = 40 cm

Therefore the area of the triangle is

A = sqrt(40(40-16)(40-30)(40-34))

A = sqrt(40(24)(10)(6))

A = sqrt(57600)

A = 240 cm2

#### Notes

No option is correct

Concept: Application of Heron’s Formula in Finding Areas of Quadrilaterals
Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 17 Heron’s Formula
Exercise 17.4 | Q 1 | Page 24

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