Mark the Correct Alternative in Each of the Following: the Sides of a Triangle Are 16 Cm, 30 Cm, 34 Cm. Its Area is - Mathematics


Mark the correct alternative in each of the following:
The sides of a triangle are 16 cm, 30 cm, 34 cm. Its area is


  • 225 cm2

  • 225  \[\sqrt{3}\] cm2

  • 225  \[\sqrt{2}\] cm2

  • 450 cm

  • none above 



The area of a triangle having sides aband s as semi-perimeter is given by,

`A = sqrt( s(s-a)(s-b)(s-c))`, where

`s = ( a+b+c)/2`

Therefore the area of a triangle say A, having sides 16 cm, 30 cm and 34 cm is given by

a = 16 cm ; b = 30 cm ; c = 34 cm

`s =  (a+b+c)/2 `

`s = (16 + 30 +34 )/2`

`s = 80/2`

s = 40 cm

Therefore the area of the triangle is 

`A = sqrt(40(40-16)(40-30)(40-34))`

`A = sqrt(40(24)(10)(6))`

`A = sqrt(57600)`

A = 240 cm2



No option is correct


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Chapter 17: Heron’s Formula - Exercise 17.4 [Page 24]


RD Sharma Mathematics for Class 9
Chapter 17 Heron’s Formula
Exercise 17.4 | Q 1 | Page 24

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