# Making use of the cube root table, find the cube root 7800 - Mathematics

Sum

Making use of the cube root table, find the cube root
7800

#### Solution

We have: $7800 = 78 \times 100$

∴ $\sqrt[3]{7800} = \sqrt[3]{78 \times 100} = \sqrt[3]{78} \times \sqrt[3]{100}$

By the cube root table, we have: $\sqrt[3]{78} = 4 . 273 \text{ and } \sqrt[3]{100} = 4 . 642$

$\sqrt[3]{7800} = \sqrt[3]{78} \times \sqrt[3]{100} = 4 . 273 \times 4 . 642 = 19 . 835 (\text{ upto three decimal places} )$

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#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 4 Cubes and Cube Roots
Exercise 4.5 | Q 7 | Page 36