# Making Use of the Cube Root Table, Find the Cube Root 5112 . - Mathematics

Sum

Making use of the cube root table, find the cube root
5112 .

#### Solution

By prime factorisation, we have: $5112 = 2^3 \times 3^2 \times 71 \Rightarrow \sqrt[3]{5112} = 2 \times \sqrt[3]{9} \times \sqrt[3]{71}$

By the cube root table, we have: $\sqrt[3]{9} = 2 . 080 and \sqrt[3]{71} = 4 . 141$

∴ $\sqrt[3]{5112} = 2 \times \sqrt[3]{9} \times \sqrt[3]{71} = 2 \times 2 . 080 \times 4 . 141 = 17 . 227$ (upto three decimal places)

Thus, the required cube root is 17.227.

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 4 Cubes and Cube Roots
Exercise 4.5 | Q 10 | Page 36