# Making Use of the Cube Root Table, Find the Cube Root 37800 . - Mathematics

Sum

Making use of the cube root table, find the cube root
37800 .

#### Solution

We have: $37800 = 2^3 \times 3^3 \times 175 \Rightarrow \sqrt[3]{37800} = \sqrt[3]{2^3 \times 3^3 \times 175} = 6 \times \sqrt[3]{175}$

Also

$170 < 175 < 180 \Rightarrow \sqrt[3]{170} < \sqrt[3]{175} < \sqrt[3]{180}$

From cube root table, we have: $\sqrt[3]{170} = 5 . 540 \text{ and } \sqrt[3]{180} = 5 . 646$

For the difference (180 - 170), i.e., 10, the difference in values

$= 5 . 646 - 5 . 540 = 0 . 106$
∴  For the difference of (175 - 170), i.e., 5, the difference in values
$= \frac{0 . 106}{10} \times 5 = 0 . 053$
∴ $\sqrt[3]{175} = 5 . 540 + 0 . 053 = 5 . 593$
Now
$37800 = 6 \times \sqrt[3]{175} = 6 \times 5 . 593 = 33 . 558$

Thus, the required cube root is 33.558.

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#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 4 Cubes and Cube Roots
Exercise 4.5 | Q 15 | Page 36