HSC Science (General) 12th Board ExamMaharashtra State Board
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Solution - Calculate the Magnetic Permeability of the Iron Rod - HSC Science (General) 12th Board Exam - Physics

Question

An iron rod of area of cross-section 0.1m2 is subjected to a magnetising field of 1000 A/m. Calculate the magnetic permeability of the iron rod. [Magnetic susceptibility of iron = 59.9, magnetic permeability of vacuum = 4π x 10-7 S. I. unit]

Solution

Given:- H= 1000 A/m, χ = 59.9, μ0 = 4π x 10-7 S.I. unit

To find:- Permeability (μ)

Formula:- μ = μ0 (1 + χ)

Calculation:- From formula,

μ = 4π x 10-7 (1 + 59.9)

   = 4 x 3.142 x 10-7 x 60.9

   = antilog [log(4) + log(3.142) + log(60.9)] x 10-7

   = antilog [0.6021 + 0.4972 + 1.7846] x 10-7

   = antilog [2.8839] x 10-7

   = 765.4 x 10-7

∴ μ = 7.654 x 10-5 Wb/A-m

The magnectic permeability of the iron rod is 7.654 x 10-5 Wb/A-m.

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Reference Material

Solution for question: Calculate the Magnetic Permeability of the Iron Rod concept: null - Magnetic Properties of Materials. For the courses HSC Science (General) , HSC Science (Electronics), HSC Science (Computer Science)
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