#### Question

A circular coil of 300 turns and average area 5 * 10^{-}^{3}m^{2} carries a current of 15A. Calculate the magnitude of magnetic moment associated with the coil.

#### Solution

No. of turns, n = 300

A = 5 × 10^{-3} m^{2}

I = 15 A

For n turns, M = nIA

M = 300 × 15 × 5 × 10^{-3}

M = 22.5 Am^{2}

Hence, the magnitude of magnetic induction associated with the coil is 22.5 Am^{2}.

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#### APPEARS IN

Solution for question: Calculate the Magnitude of Magnetic Moment Associated with the Coil. concept: Magnetic Dipole Moment of a Revolving Electron. For the courses HSC Science (Computer Science), HSC Science (Electronics), HSC Science (General)