HSC Science (General) 12th Board ExamMaharashtra State Board
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# An Electron in an Atom Revolves Around the Nucleus in an Orbit of Radius 0.53 Å. If the Frequency of Revolution of an Electron - HSC Science (General) 12th Board Exam - Physics

ConceptMagnetic Dipole Moment of a Revolving Electron

#### Question

An electron in an atom revolves around the nucleus in an orbit of radius 0.53 Å. If the frequency of revolution of an electron is 9 x109 MHz, calculate the orbital  angular momentum

[Given : Charge on an electron = 1.6 x 10–19 C; Gyromagnetic ratio = 8.8 x 1010 C/kg; π = 3.142]

#### Solution 1

Given : Charge on an electron = 1.6 x 10–19 C;
Gyromagnetic ratio = 8.8 x 1010 C/kg; π = 3.142

#### Solution 2

Given : Charge on an electron = 1.6 x 10–19 C;
Gyromagnetic ratio = 8.8 x 1010 C/kg; π = 3.142

Formula:  L_0=M_0/"gyromagneticratio"

M=IA

Since I=1/T e=fe

From formula

M=feA=fepir^2

=9xx10^15xx1.6xx10^-19xxpixx(0.53xx10^-10)^2

=1.6xxpixx0.25xx10^-23

M=1.270xx10^-23 Am^2

Using formula L_0=(1.270xx10^-23)/(8.8 xx10^10)

L_0=0.1443xx10^-33 (kgm^2)/s

#### Solution 3

Given : Charge on an electron = 1.6 x 10–19 C;
Gyromagnetic ratio = 8.8 x 1010 C/kg; π = 3.142

Formula:  L_0=M_0/"gyromagneticratio"

M=IA

Since I=1/T e=fe

From formula

M=feA=fepir^2

=9xx10^15xx1.6xx10^-19xxpixx(0.53xx10^-10)^2

=1.6xxpixx0.25xx10^-23

M=1.270xx10^-23 Am^2

Using formula L_0=(1.270xx10^-23)/(8.8 xx10^10)

L_0=0.1443xx10^-33 (kgm^2)/s

Is there an error in this question or solution?

#### APPEARS IN

2016-2017 (March) (with solutions)
Question 7.4 | 3.00 marks
Solution An Electron in an Atom Revolves Around the Nucleus in an Orbit of Radius 0.53 Å. If the Frequency of Revolution of an Electron Concept: Magnetic Dipole Moment of a Revolving Electron.
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