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# Δ Lmn is an Equilateral Triangle. Lm = 14 Cm. as Shown in the Figure, Three Sectors Are Drawn with Vertices as Centers and Radius 7 Cm. Find, Area of Any One of the Sector - Geometry

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ConceptAreas of Sector and Segment of a Circle

#### Question

$∆$ LMN is an equilateral triangle. LM = 14 cm. As shown in the figure, three sectors are drawn with vertices as centers and radius 7 cm.
Find, Area of any one of the sectors.

#### Solution

∆LMN is an equilateral triangle.
∴ LM = MN = LN = 14 cm
∠L = ∠M = ∠N = 90º

Radius of the each sector, r = 7 cm
Area of any one of the sectors =$\frac{\theta}{360° } \times \pi r^2 = \frac{60° }{360° } \times \frac{22}{7} \times \left( 7 \right)^2$  = 25.67 cm2

Is there an error in this question or solution?

#### APPEARS IN

Balbharati Solution for Balbharati Class 10 Mathematics 2 Geometry (2018 to Current)
Chapter 7: Mensuration
Practice set 7.3 | Q: 13.2 | Page no. 155
Solution Δ Lmn is an Equilateral Triangle. Lm = 14 Cm. as Shown in the Figure, Three Sectors Are Drawn with Vertices as Centers and Radius 7 Cm. Find, Area of Any One of the Sector Concept: Areas of Sector and Segment of a Circle.
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