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Δ Lmn is an Equilateral Triangle. Lm = 14 Cm. as Shown in the Figure, Three Sectors Are Drawn with Vertices as Centers and Radius 7 Cm. Find, Area of Any One of the Sector - Geometry

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Sum
∆LMN is an equilateral triangle. LM = 14 cm. As shown in the figure, three sectors are drawn with vertices as centers and radius 7cm. Find, Area of any one of the sectors.
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Solution

∆LMN is an equilateral triangle.

Since LMN is equilateral, L = M = N = 60˚

Given r = 7

Area of sector = `(θ/360)` πr2

Area of sector = `(60/360) xx 22/7 xx 7^2`

= `11 xx 7/3`

= 25.67 cm2

Hence area of one sector = 25.67 cm2

Concept: Areas of Sector and Segment of a Circle
  Is there an error in this question or solution?

APPEARS IN

Balbharati Mathematics 2 Geometry 10th Standard SSC Maharashtra State Board
Chapter 7 Mensuration
Practice set 7.3 | Q 13.2 | Page 155
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