∆LMN is an equilateral triangle. LM = 14 cm. As shown in the figure, three sectors are drawn with vertices as centers and radius 7cm. Find, Area of any one of the sectors.
∆LMN is an equilateral triangle.
Since LMN is equilateral, L = M = N = 60˚
Given r = 7
Area of sector = `(θ/360)` πr2
Area of sector = `(60/360) xx 22/7 xx 7^2`
= `11 xx 7/3`
= 25.67 cm2
Hence area of one sector = 25.67 cm2
Concept: Areas of Sector and Segment of a Circle
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