# Δ Lmn is an Equilateral Triangle. Lm = 14 Cm. as Shown in the Figure, Three Sectors Are Drawn with Vertices as Centers and Radius 7 Cm. Find, Area of Any One of the Sector - Geometry

Sum
∆LMN is an equilateral triangle. LM = 14 cm. As shown in the figure, three sectors are drawn with vertices as centers and radius 7cm. Find, Area of any one of the sectors.

#### Solution

∆LMN is an equilateral triangle.

Since LMN is equilateral, L = M = N = 60˚

Given r = 7

Area of sector = (θ/360) πr2

Area of sector = (60/360) xx 22/7 xx 7^2

= 11 xx 7/3

= 25.67 cm2

Hence area of one sector = 25.67 cm2

Concept: Areas of Sector and Segment of a Circle
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#### APPEARS IN

Balbharati Mathematics 2 Geometry 10th Standard SSC Maharashtra State Board
Chapter 7 Mensuration
Practice set 7.3 | Q 13.2 | Page 155