Δ Lmn is an Equilateral Triangle. Lm = 14 Cm. as Shown in Figure, Three Sectors Are Drawn with Vertices as Centres and Radius 7 Cm. Find, Area of the Shaded Region. - Geometry

Sum
$∆$ LMN is an equilateral triangle. LM = 14 cm. As shown in the figure, three sectors are drawn with vertices as centers and radius 7 cm.
Find, Area of the shaded region.

Solution

∆LMN is an equilateral triangle.
∴ LM = MN = LN = 14 cm
∠L = ∠M = ∠N = 90º

Area of the shaded region = Area of ∆LMN − Total area of all the three sectors = 84.87 − 77.01 = 7.86 cm2

Is there an error in this question or solution?

APPEARS IN

Balbharati Mathematics 2 Geometry 10th Standard SSC Maharashtra State Board
Chapter 7 Mensuration
Practice set 7.3 | Q 13.4 | Page 155
Share