Sum

\[∆\] LMN is an equilateral triangle. LM = 14 cm. As shown in the figure, three sectors are drawn with vertices as centers and radius 7 cm.

Find, Area of the shaded region.

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#### Solution

∆LMN is an equilateral triangle.

∴ LM = MN = LN = 14 cm

∠L = ∠M = ∠N = 90º

Area of the shaded region = Area of ∆LMN − Total area of all the three sectors = 84.87 − 77.01 = 7.86 cm^{2}

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