#### Question

\[∆\] LMN is an equilateral triangle. LM = 14 cm. As shown in the figure, three sectors are drawn with vertices as centers and radius 7 cm.

Find, A ( \[∆\] LMN)

#### Solution

∆LMN is an equilateral triangle.

∴ LM = MN = LN = 14 cm

∠L = ∠M = ∠N = 90º Area of ∆LMN = \[\frac{\sqrt{3}}{4} \left( \text{ Side} \right)^2 = \frac{\sqrt{3}}{4} \times \left( 14 \right)^2 = \frac{1 . 732}{4} \times 196\] =84.87 cm^{2}

Is there an error in this question or solution?

Solution Δ Lmn is an Equilateral Triangle. Lm = 14 Cm. as Shown in Figure, Three Sectors Are Drawn with Vertices as Centres and Radius 7 Cm. Find, a ( δ Lmn) Concept: Areas of Sector and Segment of a Circle.