Maharashtra State Board course SSC (English Medium) Class 10th Board Exam
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Δ Lmn is an Equilateral Triangle. Lm = 14 Cm. as Shown in Figure, Three Sectors Are Drawn with Vertices as Centres and Radius 7 Cm. Find, a ( δ Lmn) - Geometry

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Question

\[∆\] LMN is an equilateral triangle. LM = 14 cm. As shown in the figure, three sectors are drawn with vertices as centers and radius 7 cm.
Find, A ( \[∆\] LMN)

Solution

∆LMN is an equilateral triangle.
∴ LM = MN = LN = 14 cm
∠L = ∠M = ∠N = 90º  Area of ∆LMN = \[\frac{\sqrt{3}}{4} \left( \text{ Side}  \right)^2 = \frac{\sqrt{3}}{4} \times \left( 14 \right)^2 = \frac{1 . 732}{4} \times 196\] =84.87 cm2

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APPEARS IN

 Balbharati Solution for Balbharati Class 10 Mathematics 2 Geometry (2018 to Current)
Chapter 7: Mensuration
Practice set 7.3 | Q: 13.1 | Page no. 155
Solution Δ Lmn is an Equilateral Triangle. Lm = 14 Cm. as Shown in Figure, Three Sectors Are Drawn with Vertices as Centres and Radius 7 Cm. Find, a ( δ Lmn) Concept: Areas of Sector and Segment of a Circle.
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