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In the given figure, if PQ || ST, ∠PQR = 110º and ∠RST = 130º, find ∠QRS. - CBSE Class 9 - Mathematics

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Question

In the given figure, if PQ || ST, ∠PQR = 110º and ∠RST = 130º, find ∠QRS.

[Hint: Draw a line parallel to ST through point R.]

Solution

Let us draw a line XY parallel to ST and passing through point R.

∠PQR + ∠QRX = 180º (Co-interior angles on the same side of transversal QR)

⇒ 110º + ∠QRX = 180º

⇒ ∠QRX = 70º

Also,

∠RST + ∠SRY = 180º (Co-interior angles on the same side of transversal SR)

130º + ∠SRY = 180º

∠SRY = 50º

XY is a straight line. RQ and RS stand on it.

∴ ∠QRX + ∠QRS + ∠SRY = 180º

70º + ∠QRS + 50º = 180º

∠QRS = 180º − 120º = 60º

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APPEARS IN

 NCERT Solution for Mathematics Class 9 (2018 to Current)
Chapter 6: Lines and Angles
Ex. 6.20 | Q: 4 | Page no. 105

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Solution In the given figure, if PQ || ST, ∠PQR = 110º and ∠RST = 130º, find ∠QRS. Concept: Lines Parallel to the Same Line.
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