Lim X → − 1 X 3 + 1 X + 1 - Mathematics

$\lim_{x \to - 1} \frac{x^3 + 1}{x + 1}$

Solution

$\lim_{x \to - 1} \left[ \frac{x^3 + 1}{x + 1} \right]$
$= \lim_{x \to - 1} \left[ \frac{x^3 - \left( - 1 \right)}{x - \left( - 1 \right)} \right]$
$= \lim_{x \to - 1} \left[ \frac{x^3 - \left( - 1 \right)^3}{x - \left( - 1 \right)} \right]$
$= 3 \left( - 1 \right)^{3 - 1}$
$= 3$

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APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 29 Limits
Exercise 29.5 | Q 10 | Page 33