Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11
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Lim X → 0 Tan 8 X Sin 2 X - Mathematics

\[\lim_{x \to 0} \frac{\tan 8x}{\sin 2x}\] 

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Solution

\[\lim_{x \to 0} \left[ \frac{\tan 8x}{\sin 2x} \right]\] 

\[\Rightarrow \lim_{x \to 0} \left[ \frac{\tan 8x}{8x} \times \frac{8x}{\frac{\sin 2x}{2x} \times 2x} \right] \left[ \because \lim_{x \to 0} \frac{\tan 8x}{8x} = 1, \lim_{x \to 0} \frac{\sin 2x}{2x} = 1 \right]\]
\[ \Rightarrow 4\]

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APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 29 Limits
Exercise 29.7 | Q 6 | Page 50
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