Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11
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Lim X → 0 E 3 + X − Sin X − E 3 X - Mathematics

\[\lim_{x \to 0} \frac{e^{3 + x} - \sin x - e^3}{x}\] 

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Solution

\[\lim_{x \to 0} \left[ \frac{e^{3 + x} - \sin x - e^3}{x} \right]\]
\[ = \lim_{x \to 0} \left[ \left( \frac{e^{3 + x} - e^3}{x} \right) - \frac{\sin x}{x} \right]\]
\[ = \lim_{x \to 0} \left[ e^3 \left( \frac{e^x - 1}{x} \right) - \frac{\sin x}{x} \right]\]
\[ = e^3 \times 1 - 1\]
\[ = e^3 - 1\]

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APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 29 Limits
Exercise 29.1 | Q 33 | Page 72
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