# Light of Wavelength 488 Nm is Produced by an Argon Laser Which is Used in the Photoelectric Effect. When Light from this Spectral Line is Incident on the Emitter, the Stopping (Cut-off) Potential of Photoelectrons is 0.38 V. Find the Work Function of the Material from Which the Emitter is Made. - Physics

Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.

#### Solution

Wavelength of light produced by the argon laser, λ = 488 nm

= 488 × 10−9 m

Stopping potential of the photoelectrons, V0 = 0.38 V

1eV = 1.6 × 10−19 J

∴ V0 = 0.38/(1.6 xx 10^(-19)) eV

Planck’s constant, h = 6.6 × 10−34 Js

Charge on an electron, e = 1.6 × 10−19 C

Speed of light, c = 3 × 10 m/s

From Einstein’s photoelectric effect, we have the relation involving the work function Φ0of the material of the emitter as:

eV_0 = (hc)/lambda - phi_0

phi_0 - (hc)/lambda - eV_0

= (6.6 xx 10^(-34 ) xx 3 xx 10^8)/(1.6 xx 10^(-19) xx  488 xx 10^(-9)) - (1.6 xx10^(-19) xx 0.38)/(1.6 xx 10^(-19))

= 2.54 - 0.38 = 2.16 eV

Therefore, the material with which the emitter is made has the work function of 2.16 eV.

Concept: Einstein’S Photoelectric Equation: Energy Quantum of Radiation
Is there an error in this question or solution?

#### APPEARS IN

NCERT Class 12 Physics Textbook
Chapter 11 Dual Nature of Radiation and Matter
Q 11 | Page 408