Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11
Advertisement Remove all ads

Let Q and W Denote the Amount of Heat Given to an Ideal Gas and the Work Done by It in an Isothermal Process. - Physics

MCQ

Let Q and W denote the amount of heat given to an ideal gas and the work done by it in an isothermal process.

Options

  • Q = 0

  •  W = 0

  • Q ≠ W

  • Q = W

Advertisement Remove all ads

Solution

 Q = W

In an isothermal process, temperature of the system stays constant, i.e. there's no change in internal energy. Thus, U = 0, where U denotes the change in internal energy of the system. According to the first law of thermodynamics, heat supplied to the system is equal to the sum of change in internal energy and work done by the system, such that Q = U + W. As U = 0, Q = W.

Concept: Kinetic Theory of Gases and Radiation - Introduction of Kinetic Theory of an Ideal Gas
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 5 Specific Heat Capacities of Gases
MCQ | Q 2 | Page 77
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×