Let n_{r} and n_{b} be the number of photons emitted by a red bulb and a blue bulb, respectively, of equal power in a given time.

#### Options

n

_{r}= n_{b}n

_{r}< n_{b}n

_{r}> n_{b}The information is insufficient to derive a relation between n

_{r}and n_{b}.

#### Solution

n_{r} > n_{b}

The two bulbs are of equal power. It means that they consume equal amount of energy per unit time.

Now, as the frequency of blue light `(f_b)` is higher than the frequency of red light `(f_r)` , `hf_b > hf_r`

Hence, the energy of a photon of blue light is more than the energy of a photon of red light.

Thus, a photon of blue light requires more energy than a photon of red light to be emitted.

For the same energy given to the bulbs in a certain time, the number of photons of blue light will be less than that of red light.

∴ `n_r > n_b` (As the amount of energy emitted from the two bulb is same)