MCQ

Let θ denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the bob is m, the tension is the string is mg cos θ

#### Options

always

never

at the extreme positions

at the mean position.

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#### Solution

at the extreme positions

Tension is the string , \[\text{T} = \frac{\text{mv}^2}{\text{r}} - \text{mg}\cos\theta\]

When v = 0,

\[\left| \text{T} \right| = \text{mg}\cos\theta\]

That is, at the extreme positions, the tension is the string is mgcosθ.

Concept: Circular Motion

Is there an error in this question or solution?

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