Answer 1

Given,
Area of parallelogram   `ABCD = 124cm^2`
Construction: draw AP ⊥ DC
Proof :
Area of parallelogram AFED = DF × AP                .......(1)
And area of parallelogram EBCF =  FC × AP           ......(2)

And DF  = FC                           .............(3)       [ F is the  midpoint of DC ]

Compare equation (1), (2) and (3)
Area of parallelogram AEFD = Area of parallelogram EBCF
∴ Area of parallelogram  ABCD  = `" Area of parallelogram"/"2"`

                                                    ` = 124 / 2 = 62cm^2`