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# Find the Value of X in the Following: 2^(5x)Div2x=Root5(2^20) - CBSE Class 9 - Mathematics

ConceptLaws of Exponents for Real Numbers

#### Question

Find the value of x in the following:

2^(5x)div2x=root5(2^20)

#### Solution

Given 2^(5x)div2x=root5(2^20)

By using rational exponents a^m/a^n=a^(m-n) we get,

2^(5x-x)=2^(20xx1/5)

2^(5x-x)=2^4

On equating the exponents we get,

5x - x = 4

4x = 4

x = 4/4

x = 1

The value of x = 1

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Solution for Mathematics for Class 9 by R D Sharma (2018-19 Session) (2018 to Current)
Chapter 2: Exponents of Real Numbers
Ex. 2.20 | Q: 10.1 | Page no. 26

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Solution Find the Value of X in the Following: 2^(5x)Div2x=Root5(2^20) Concept: Laws of Exponents for Real Numbers.
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