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Find the Value of X in the Following: `2^(5x)Div2x=Root5(2^20)` - CBSE Class 9 - Mathematics

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Question

Find the value of x in the following:

`2^(5x)div2x=root5(2^20)`

Solution

Given `2^(5x)div2x=root5(2^20)`

By using rational exponents `a^m/a^n=a^(m-n)` we get,

`2^(5x-x)=2^(20xx1/5)`

`2^(5x-x)=2^4`

On equating the exponents we get,

5x - x = 4

4x = 4

x = 4/4

x = 1

The value of x = 1

  Is there an error in this question or solution?

APPEARS IN

 RD Sharma Solution for Mathematics for Class 9 by R D Sharma (2018-19 Session) (2018 to Current)
Chapter 2: Exponents of Real Numbers
Ex. 2.20 | Q: 10.1 | Page no. 26

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Solution Find the Value of X in the Following: `2^(5x)Div2x=Root5(2^20)` Concept: Laws of Exponents for Real Numbers.
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