How much time would it take to distribute one Avogadro number of wheat grains, if 1010 grains are distributed each second?
Avogadro number = 6.02 × 1023
Thus, time required
`= (6.02 xx 10^(23))/10^10 s`
`= 6.02 xx 10^23 s`
`= (6.02 xx 10^23)/(60xx60xx24xx365)` year
`= 1.909 xx 10^6` year
Hence, the time taken would be `1.909 xx 10^(6)` year
Time taken to distribute `10^10` grain =1 s
Time taken to distribute = `6.022 xx 10^23 "grain"`
`= (1 s xx 6.022 xx 10^23 "gain")/(10^10 "grain")`
=` (6.022 xx 10^13)/(60xx60xx24xx365) ` = `1.9 xx 10^6` yr
The density of a gas is found to be 5.46 g/dm3 at 27 °C at 2 bar pressure. What will be its density at STP?
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The drain cleaner, Drainex contains small bits of aluminum which react with caustic soda to produce dihydrogen. What volume of dihydrogen at 20 °C and one bar will be released when 0.15g of aluminum reacts?
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- Laws of Chemical Combination - Avogadro Law