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# Density of a Gas is Found to Be 5.46 G/Dm3 at 27 °C at 2 Bar Pressure. What Will Be Its Density at Stp? - CBSE (Science) Class 11 - Chemistry

ConceptLaws of Chemical Combination Avogadro Law

#### Question

The density of a gas is found to be 5.46 g/dm3 at 27 °C at 2 bar pressure. What will be its density at STP?

#### Solution 1

Given

d_1= 5.46 "g/dm"^3

p_1 =  2bar

T_1 = 27 ^@C = (27 + 273) K = 300 K

p_2 =  1 bar

T_2 = 273 K

d_2= ?

The density (d2) of the gas at STP can be calculated using the equation,

d = (Mp)/(RT)

:. d_1/d_2 = ((Mp_1)/(RT_1))/((Mp_2)/(RT_2))

=> d_1/d_2 = (p_1T_2)/(p_2T_1)

=> d_2 = (p_2T_1d_1)/(p_1T_2)

= (1xx300 xx 5.46)/(2xx273)

= 3 gdm^(-3)

Hence, the density of the gas at STP will be 3 g dm–3.

#### Solution 2

d = (MP)/(RT) For the same gas at different temperature  and pressure, d_1/d_2 = P_1/T_1 xx T_2/P_2

Here d_1 = 5.46 g dm^(-3), T_1 = 27^@C = 300 K, P_1= 2 "bar"

At STP, d_2 = ? , T_2 = 0 ^@C = 273 K,  P_2 =  1 bar

:. (5.46 g dm^(-3))/(d^2) = "2 bar"/(300 K) xx (273 K)/"1 bar"  or d_2 =  3 gdm^(-3)`

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Solution Density of a Gas is Found to Be 5.46 G/Dm3 at 27 °C at 2 Bar Pressure. What Will Be Its Density at Stp? Concept: Laws of Chemical Combination - Avogadro Law.
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