HSC Science (Computer Science) 12th Board ExamMaharashtra State Board
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State an Expression for K. E. (Kinetic Energy) and P. E. (Potential Energy) at Displacement ‘X’ for a Particle Performing Linear S.H. M. Represent Them Graphically. Find the Displacement at Which K. E. is Equal to P. E. - HSC Science (Computer Science) 12th Board Exam - Physics

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Question

State an expression for K. E. (kinetic energy) and P. E. (potential energy) at displacement ‘x’ for a particle performing linear S.H. M. Represent them graphically. Find the displacement at which K. E. is equal to P. E.

Solution

`:.K.E.=1/2mw^2(A^2-X^2)`

`P.E.=1/2mw^2X^2`

K.E. = P.E.

`1/2K(A^2-X^2)=1/2KX^2`

∴ A2=2X2

 

`:.X^2=A^2/2`

`:.X=A/sqrt2`

  Is there an error in this question or solution?

APPEARS IN

 2013-2014 (March) (with solutions)
Question 2.3 | 3.00 marks

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Solution State an Expression for K. E. (Kinetic Energy) and P. E. (Potential Energy) at Displacement ‘X’ for a Particle Performing Linear S.H. M. Represent Them Graphically. Find the Displacement at Which K. E. is Equal to P. E. Concept: K.E.(Kinetic Energy) and P.E.(Potential Energy) in S.H.M..
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