#### Question

Calculate the average molecular kinetic energy :

(a) per kilomole, (b) per kilogram, of oxygen at 27°C.

(R = 8320 J/k mole K, Avogadro's number = 6*03 x 10^{26} molecules/K mole)

clickto share

#### Solution

Given that

Temperature = 27°C = (273 + 27) K = 300 K

(a) `"Average kinetic energy per kilo mole" = 3/2RT`

`=3/2xx 8320 J/K "mole" xx300 K`

`=3.744 xx 10^6J`

(b) `"Kinetic energy per kilogram"="Kinetic energy per kilo mole"/"Molecular weight"`

`"Molecular weight of oxygen"= 32`

`"Kinetic energy per kilogram"=(3.744xx10^6 J)/32=0.117xx10^6 J`

Is there an error in this question or solution?

#### APPEARS IN

#### Related QuestionsVIEW ALL [6]

Solution for question: Calculate the Average Molecular Kinetic Energy : (A) per Kilomole, (B) per Kilogram, of Oxygen at 27°C. concept: null - K.E.(Kinetic Energy) and P.E.(Potential Energy) in S.H.M.. For the courses HSC Science (General) , HSC Science (Electronics), HSC Science (Computer Science)