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# Solution - Calculate the Average Molecular Kinetic Energy : (A) per Kilomole, (B) per Kilogram, of Oxygen at 27°C. - HSC Science (Computer Science) 12th Board Exam - Physics

ConceptK.E.(Kinetic Energy) and P.E.(Potential Energy) in S.H.M.

#### Question

Calculate the average molecular kinetic energy :

(a) per kilomole, (b) per kilogram, of oxygen at 27°C.

(R = 8320 J/k mole K, Avogadro's number = 6*03 x 1026 molecules/K mole)

#### Solution

Given that

Temperature = 27°C = (273 + 27) K = 300 K

(a) "Average kinetic energy per kilo mole" = 3/2RT

=3/2xx 8320 J/K "mole" xx300 K

=3.744 xx 10^6J

(b) "Kinetic energy per kilogram"="Kinetic energy per kilo mole"/"Molecular weight"

"Molecular weight of oxygen"= 32

"Kinetic energy per kilogram"=(3.744xx10^6 J)/32=0.117xx10^6 J

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#### Video TutorialsVIEW ALL [1]

Solution for question: Calculate the Average Molecular Kinetic Energy : (A) per Kilomole, (B) per Kilogram, of Oxygen at 27°C. concept: K.E.(Kinetic Energy) and P.E.(Potential Energy) in S.H.M.. For the courses HSC Science (Computer Science), HSC Science (Electronics), HSC Science (General)
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