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Judge the equivalent resistance when the following are connected in parallel - Science

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Judge the equivalent resistance when the following are connected in parallel − (a) 1 Ω and 106Ω, (b) 1 Ω and 103Ω and 106Ω.

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Solution

(a) When 1 Ω and 106 Ω are connected in parallel:
Let R be the equivalent resistance.

1/R=1/1+1/10^6

`R=10^6/(1+10^6)~~10^6/10^6=1 Omega`

Therefore, equivalent resistance ≈ 1 Ω

(b) When 1Ω, 103 Ω and 106 Ω are connected in parallel:

Let R be the equivalent resistance.

`1/R=1/1+1/10^3+1/10^6.(10^6+10^3+1)/10^6`

`R=1000000/1001001=0.999 Omega`

Therefore, equivalent resistance = 0.999 Ω

Concept: System of Resistors - Resistors in Series
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APPEARS IN

NCERT Class 10 Science
Chapter 12 Electricity
Q 1 | Page 216
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