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Jiya walks 6 km due east and then 8 km due north. How far is she from her starting place?

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#### Solution

Let A be the starting point and B be the ending point of Jiya.

Since ∆ABC is right-angled.

∴ (AB)^{2} = (AC)^{2} + (BC)^{2}

⇒ (AB)^{2} = 6^{2} + 8^{2}

= 36 + 64

= 100

⇒ AB = 10

Thus, Jiya is 10 km away from her starting place.

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