#### Question

It is required to construct a 10 µF capacitor which can be connected across a 200 V battery. Capacitors of capacitance 10 µF are available but they can withstand only 50 V. Design a combination which can yield the desired result.

#### Solution

Let the number of capacitors in series (connected in a row) be *x*.

The maximum voltage that the capacitors can withstand is 50 V.

The voltage across each row should be equal to 200 V.

Therefore,*x* × 50 = 200

Thus,*x* = 4 capacitors

Now,

Let there be *y* such rows.

So, the equivalent capacitance of the combination will be *xy.*

⇒* xy *= 10

⇒ *y* = 10 *x* = 4 capacitors

Thus, to yield the required result, the combination of 4 rows, each of 4 capacitors having capacitance 10 µF and breakdown voltage 50 V, is required.

Is there an error in this question or solution?

Solution It is Required to Construct a 10 µF Capacitor Which Can Be Connected Across a 200 V Battery. Capacitors of Capacitance 10 µF Are Available but They Can Withstand Only 50 V. Design a Combination Concept: Capacitors and Capacitance.