It is given that ΔABC ~ ΔPQR, with BCQR=13. Then, ar(PRQ)ar(BCA) is equal to ______. - Mathematics

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MCQ
Fill in the Blanks

It is given that ΔABC ~ ΔPQR, with `(BC)/(QR) = 1/3`. Then, `(ar(PRQ))/(ar(BCA))` is equal to ______.

Options

  • 9

  • 3

  • `1/3`

  • `1/9`

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Solution

It is given that ΔABC ~ ΔPQR, with `(BC)/(QR) = 1/3`. Then, `(ar(PRQ))/(ar(BCA))` is equal to 9.

Explanation:

Given, ∆ABC ~ ∆QR and `(BC)/(QR) = 1/3`

We know that, the ratio of the areas of two similar triangles is equal to square of the ratio of their corresponding sides.

∴ `(ar(∆PRQ))/(ar(∆BCA)) = (QR)^2/(BC)^2 = ((QR)/(BC))^2`

= `(3/1)^2`

= `9/1`

= 9

Concept: Similarity of Triangles
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APPEARS IN

NCERT Mathematics Exemplar Class 10
Chapter 6 Triangles
Exercise 6.1 | Q 8 | Page 62
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