Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
Advertisement Remove all ads

Is Placed Horizontally with the North Pole Pointing Towards East. Find the Position of the Neutral Point If the Horizontal Component of the Earth'S Magnetic Field is 18 μT. - Physics

Sum

A magnetic dipole of magnetic moment `0.72sqrt(2) "Am"^2` is placed horizontally with the north pole pointing towards east. Find the position of the neutral point if the horizontal component of the earth's magnetic field is 18 μT.

Advertisement Remove all ads

Solution

Given :
Magnetic moment of magnetic dipole,`M = 0.72sqrt(2)  "A-m"^2`

Horizontal component of the earth's magnetic field,`B_H = 18  "uT"`

Let d be the distance of neutral point from the dipole.

Magnetic field due to the bar magnet (B) on the equatorial line of the dipole is given by,

`B = (u_0)/(4pi) M/(d^3)`

⇒ `(4pi xx 10^-7)/(4pi) xx (0.72sqrt(2))/d^3 = 18 xx 10^-6`

⇒ `d^3 = (0.72 xx 1.414 xx 10^-7)/(18 xx 10^-6)`

⇒ `d^3 = 0.005656`

⇒ `d = root(3)(0.005656)`

⇒ `d ≈ 0.2  "m" = 20  "cm"`

Concept: Torque on a Magnetic Dipole (Bar Magnet) in a Uniform Magnetic Field
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 14 Permanent Magnets
Q 10 | Page 277
Advertisement Remove all ads

Video TutorialsVIEW ALL [1]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×