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# Calculate the Ph of the Following Solutions: 2 G of Tloh Dissolved in Water to Give 2 Litre of Solution. - CBSE (Science) Class 11 - Chemistry

ConceptIonization of Acids and Bases The pH Scale

#### Question

Calculate the pH of the following solutions: 2 g of TlOH dissolved in water to give 2 litre of solution.

#### Solution 1

Molar conc. of TlOH =(2g)/((204 + 16 + 1) g mol^(-1)) xx 1/(2L) = 4.52 xx 10^(-3) M

TlOH^-] = [TlOH] = 4.52 xx 10^(-3) M

[H^+] = 10^(-14)/((4.52 xx 10^(-3))) = 2.21 xx 10^(-12) M

pH = -log(2.21 xx 10^(-12)) = 12 - (0.3424) = 11.66

#### Solution 2

For 2g of TlOH dissolved in water to give 2 L of solution:

[TlOH_(aq)] = 2/2 "g/L"

 =2/2 xx 1/221 M

= 1/221 M

TlOH_(aq) -> Tl_(aq)^+ + OH_(aq)^-

[TlOH_(aq)^(-)] = [TlOH_(aq)] = 1/221 M

K_M = [H^+ ][OH^-]

10^(-14) = [H^+] (1/221)

221 xx 10^(-14) = [H+]

=> pH = -log [H^+] = -log(221xx10^(-14))

= -log(2.21 xx 10^(-12))

= 11.65

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Solution Calculate the Ph of the Following Solutions: 2 G of Tloh Dissolved in Water to Give 2 Litre of Solution. Concept: Ionization of Acids and Bases - The pH Scale.
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