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Calculate the Ph of the Following Solutions: 2 G of Tloh Dissolved in Water to Give 2 Litre of Solution. - CBSE (Science) Class 11 - Chemistry

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Question

Calculate the pH of the following solutions: 2 g of TlOH dissolved in water to give 2 litre of solution.

Solution 1

Molar conc. of TlOH =`(2g)/((204 + 16 + 1) g mol^(-1)) xx 1/(2L) = 4.52 xx 10^(-3) M`

`TlOH^-] = [TlOH] = 4.52 xx 10^(-3) M`

`[H^+] = 10^(-14)/((4.52 xx 10^(-3))) = 2.21 xx 10^(-12) M`

`pH = -log(2.21 xx 10^(-12)) = 12 - (0.3424) = 11.66`

 

Solution 2

For 2g of TlOH dissolved in water to give 2 L of solution:

`[TlOH_(aq)] = 2/2 "g/L"`

` =2/2 xx 1/221 M`

`= 1/221 M`

`TlOH_(aq) -> Tl_(aq)^+ + OH_(aq)^-`

`[TlOH_(aq)^(-)] = [TlOH_(aq)] = 1/221 M`

`K_M = [H^+ ][OH^-]`

`10^(-14) = [H^+] (1/221)`

`221 xx 10^(-14) = [H+]`

`=> pH = -log [H^+] = -log(221xx10^(-14))`

`= -log(2.21 xx 10^(-12))`

= 11.65

 

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Solution Calculate the Ph of the Following Solutions: 2 G of Tloh Dissolved in Water to Give 2 Litre of Solution. Concept: Ionization of Acids and Bases - The pH Scale.
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