#### Question

In the below given figure, a tower AB is 20 m high and BC, its shadow on the ground, is 20√3 m long. Find the sun’s altitude.

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#### Solution

LetAB be the tower and BC be its shadow.

AB = 20, BC = 20√3

In ΔABC,

`tan theta= `

`tan theta=20/(20sqrt3)`

`tan theta=1/sqrt3`

`but,tan30=1/sqrt3`

`theta=30^@`

The Sun is at an altitude of 30º .

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#### Reference Material

Solution for question: In the below given figure, a tower AB is 20 m high and BC, its shadow on the ground, is 20√3 m long. Find the sun’s altitude. concept: null - Introduction to Trigonometry Examples and Solutions. For the course CBSE