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# A Flooring Tile Has the Shape of a Parallelogram Whose Base is 24 Cm and the Corresponding Height is 10 Cm. How Many Such Tiles Are Required to Cover a Floor of Area 1080 M2? (If Required You Can Split the Tiles in Whatever Way You Want to Fill up the Corners). - CBSE Class 8 - Mathematics

ConceptIntroduction of Mensuration

#### Question

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2? (If required you can split the tiles in whatever way you want to fill up the corners).

#### Solution

Area of parallelogram = Base × Height

Hence, area of one tile = 24 cm × 10 cm = 240 cm2

Required number of tiles = "Area of Floor"/"Area of each tile"

= (1080 m^2)/(240 cm^2) = ((1080 xx 10000) cm^2)/(240 cm^2)   (∵ 1m = 100 cm)= 45000 tiles.

Thus, 45000 tiles are required to cover a floor of area 1080 m2.

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#### APPEARS IN

NCERT Solution for Mathematics Textbook for Class 8 (2018 to Current)
Chapter 11: Mensuration
Ex. 11.10 | Q: 4 | Page no. 171
Solution A Flooring Tile Has the Shape of a Parallelogram Whose Base is 24 Cm and the Corresponding Height is 10 Cm. How Many Such Tiles Are Required to Cover a Floor of Area 1080 M2? (If Required You Can Split the Tiles in Whatever Way You Want to Fill up the Corners). Concept: Introduction of Mensuration.
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