HSC Commerce (Marketing and Salesmanship) 12th Board ExamMaharashtra State Board
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Find the Inverse of the Matrix A= [ 1 2 1 3 ] Using Elementry Transformations. - HSC Commerce (Marketing and Salesmanship) 12th Board Exam - Mathematics and Statistics

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Question

Find the inverse of the matrix A=`[[1,2],[1,3]]` using elementry transformations.  

Solution

A=`[[1,2],[1,3]]` 

|A|=3-2

   =1≠ 0 

∴`A_1` exists

We have `A=A^-1=I` 

`[[1,2],[1,3]]A^1`=`[[1,0],[0,1]]` 

Applying` R_2→R_2-R_1` 

`[[1 ,2],[0,1]]A^1=[[1,0],[-1, 1]]` 

Applying `R_1→R_1-2R_2` 

`[[1,0],[0,1]]A^1=[[3,-2],[-1 ,1]]` 

Hence `A^-1=[[3,-2],[-1,1]]`

  Is there an error in this question or solution?

APPEARS IN

 2017-2018 (March) (with solutions)
Question 1.2 | 2.00 marks
Solution Find the Inverse of the Matrix A= [ 1 2 1 3 ] Using Elementry Transformations. Concept: Introduction of Matrices.
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