Share

# A reaction is first order in A and second order in B. How is the rate affected when the concentrations of both A and B are doubled? - Chemistry

#### Question

A reaction is first order in A and second order in B. How is the rate affected when the concentrations of both A and B are doubled?

#### Solution

When the concentrations of both A and B are doubled,

-(d[R])/dt = k [A][B]^2

= k[2A][2B]^2

=8.k[A][B]^2

Therefore, the rate of reaction will increase 8 times.

Is there an error in this question or solution?