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A reaction is first order in A and second order in B. How is the rate affected when the concentrations of both A and B are doubled? - Chemistry

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Question

A reaction is first order in A and second order in B. How is the rate affected when the concentrations of both A and B are doubled?

 

Solution

When the concentrations of both A and B are doubled,

`-(d[R])/dt = k [A][B]^2`

`= k[2A][2B]^2`

`=8.k[A][B]^2`

Therefore, the rate of reaction will increase 8 times.

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APPEARS IN

 NCERT Solution for Chemistry Textbook for Class 12 (2018 (Latest))
Chapter 4: Chemical Kinetics
Q: 9.3 | Page no. 118
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A reaction is first order in A and second order in B. How is the rate affected when the concentrations of both A and B are doubled? Concept: Integrated Rate Equations - First Order Reactions.
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