Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Sum
Integrate the following with respect to x:
`4 cos(5 - 2x) + 9"e"^(3x - 6) + 24/(6 - 4x)`
Advertisement Remove all ads
Solution
`int [4 cos(5 - 2x) + 9"e"^(3x - 6) + 24/(6 - 4x)] "d"x`
= `4 int cos(5 - 2x) "d"x + 9 int "e"^(3x - 6) "d"x + 24 int 1/(6 - 4x) "d"x`
= `(- 4)/2 cos (5 - 2x) + 9/3 "e"^(3x - 6) + 24/(- 4) log |6 - 4x| "d"x`
= `- 2 cos(5 - 2x) + 3"e"^(3x - 6) - 6 log|6 - 4x| + "c"`
Concept: Properties of Integrals
Is there an error in this question or solution?
