HSC Science (Computer Science) 12th Board ExamMaharashtra State Board
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# The accumulator in 8085 microprocessor contains data 71H and register E contains data 39H. What will be the contents of an accumulator in Hexadecimal after execution of the following  instructions independently - HSC Science (Computer Science) 12th Board Exam - Computer Science 2

ConceptInstruction Set and Programming of 8085

#### Question

The accumulator in 8085 microprocessor contains data 71H and register E contains data 39H. What will be the contents of an accumulator in  Hexadecimal after execution of the following  instructions independently ?

(ii) ORA E
(iii) RRC

#### Solution

Before execution : [A] = 71H

71 H = 0 1 1 1 0 0 0 1
ADD 39 H =  0 0 1 1 1 0 0 1
1 0 1 0 1 0 1 0 = AA H
After execution [A] = AA H
[Cy] = 00H

(ii) ORA E : Logically OR with Acc
Before execution : [A] = 71H

Instruction : ORA E

71 H = 0 1 1 1 0 0 0 1

ORA 39 H = 0 0 1 1 1 0 0 1

0 1 1 1 1 0 0 1 = 79 H

After execution : [A] = 79H

RRC : Rotate accumulator right by one bit.
Before execution : [A] = 71H 0 1 1 1 0 0 0 1

Instruction : RRC
After execution [A] = 1 0 1 1 1 0 0 0 = B8 H

∴[A] = B8H
[Cy] = 01H

Is there an error in this question or solution?

#### APPEARS IN

2016-2017 (March) (with solutions)
Question 2.1.3 | 3.00 marks
Solution The accumulator in 8085 microprocessor contains data 71H and register E contains data 39H. What will be the contents of an accumulator in Hexadecimal after execution of the following  instructions independently Concept: Instruction Set and Programming of 8085.
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