CBSE Class 9CBSE
Share
Notifications

View all notifications

In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. - CBSE Class 9 - Mathematics

Login
Create free account


      Forgot password?

Question

In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC.

Solution

In ΔAOB,

∠B < ∠A

⇒ AO < BO (Side opposite to smaller angle is smaller) ... (1)

In ΔCOD,

∠C < ∠D

⇒ OD < OC (Side opposite to smaller angle is smaller) ... (2)

On adding equations (1) and (2), we obtain

AO + OD < BO + OC

AD < BC

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Mathematics Class 9 (2018 to Current)
Chapter 7: Triangles
Ex. 7.40 | Q: 3 | Page no. 132

Video TutorialsVIEW ALL [1]

Solution In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. Concept: Inequalities in a Triangle.
S
View in app×