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Solution - AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD (see the given figure). Show that ∠A > ∠C and ∠B > ∠D. - Inequalities in a Triangle

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ConceptInequalities in a Triangle  

Question

AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD (see the given figure). Show that ∠A > ∠C and ∠B > ∠D.

Solution

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Reference Material

Solution for question: AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD (see the given figure). Show that ∠A > ∠C and ∠B > ∠D. concept: Inequalities in a Triangle. For the course CBSE
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