#### Question

The currents flowing in the two coils of self-inductance L_{1} = 16 mH and L_{2} = 12 mH are increasing at the same rate. If the power supplied to the two coil is equal, find the ratio of the energies stored in the two coils at a given instant ?

#### Solution

Energy stored, \[E = \frac{1}{2}L I^2\]

\[\frac{E_1}{E_2} = \frac{L_1 {I_1}^2}{L_2 {I_2}^2} = \frac{16}{12} \times \frac{9}{16} = \frac{3}{4}\]

\[ \Rightarrow \frac{E_1}{E_2} = \frac{3}{4}\]

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Solution The Currents Flowing in the Two Coils of Self-inductance L1 = 16 Mh and L2 = 12 Mh Are Increasing at the Same Rate. If the Power Supplied to the Two Coil is Equal, Find the Ratio of the Energies Store Concept: Inductance - Self-Inductance.