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Current in a Circuit Falls from 5.0 a to 0.0 a in 0.1 S. If an Average Emf of 200 V Induced, Give an Estimate of the Self-inductance of the Circuit. - Physics

Question

Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self-inductance of the circuit.

Solution

Initial current, I1 = 5.0 A

Final current, I2 = 0.0 A

Change in currentdI=I_1-I_2=5A,

Time taken for the change, t = 0.1 s

Average emf, e = 200 V

For self-inductance (L) of the coil, we have the relation for average emf as:

e = L "di"/"dt"

L=e/((di)/(dt))

=200/(5/0.1)=4H

Hence, the self induction of the coil is 4 H.

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