HSC Science (Electronics) 12th Board ExamMaharashtra State Board
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Solution - The co-efficient of mutual induction between primary and secondary coil is 2H. Calculate induced e.m.f. - HSC Science (Electronics) 12th Board Exam - Physics

Question

The co-efficient of mutual induction between primary and secondary coil is 2H. Calculate induced e.m.f. if current of 4A is cut off in 2.5 x 10-4 seconds

Solution

Here, the co-efficient of mutual induction, M = 2H

4A is cut-off in 2.5 × 10-4 seconds.

Induced e.m.f., E = `M(di)/(dt)`

`therefore E = 2Hxx(4A)/(2.5xx10^-4)`

`therefore E = 3.2 xx 10^4V`

 

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Reference Material

Solution for question: The co-efficient of mutual induction between primary and secondary coil is 2H. Calculate induced e.m.f. concept: null - Mutual Inductance. For the courses HSC Science (Electronics), HSC Science (General) , HSC Science (Computer Science)
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