HSC Science (Electronics) 12th Board ExamMaharashtra State Board
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# Solution - A Solenoid 3.142m Long and 5.0 Cm in Diameter Has Two Layers of Windings of 500 Turns Each and Carries a Current of 5a. Calculate the Magnetic Induction at Its Centre Along the Axis. - HSC Science (Electronics) 12th Board Exam - Physics

ConceptInductance and Capacitance

#### Question

A solenoid 3.142m long and 5.0 cm in diameter has two layers of windings of 500 turns each and carries a current of 5A. Calculate the magnetic induction at its centre along the axis.

#### Solution

Given:

Length of solenoid, l = 3.142m

Diameter, d = 5.0cm = 5 × 10-2m

Radius, r = 2.5cm = 2.5 × 10-2m

No. of turns, N = 2 × 500 = 1000

Current, I = 5A

To calculate:

The magnetic induction at its centre along the axis.

Magnetic Induction, B = ?

Formula:

B = μonI

Solution:

"B"=mu_o("N"/"l")"I"

therefore"B"=(4pixx10^-7xx1000xx5)/3.142

therefore"B"=2xx10^-3 "T"

Hence, the magnetic induction at the centre of the circular loop along its axis is 2 × 10-3T.

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#### APPEARS IN

Solution for question: A Solenoid 3.142m Long and 5.0 Cm in Diameter Has Two Layers of Windings of 500 Turns Each and Carries a Current of 5a. Calculate the Magnetic Induction at Its Centre Along the Axis. concept: null - Inductance and Capacitance. For the courses HSC Science (Electronics), HSC Science (Computer Science), HSC Science (General)
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