#### Question

evaluate : `int xcosxdx`

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#### Solution

`"Let " I=int x cosx dx`

integrating by parts

`I=x int cosx dx-int[d/dx(x)int cosxdx]dx`

`=xsinx-int(sinx)dx+c`

`=xsinx-(-cosx)+c`

`=xsinx+cosx+c`

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Solution for question: evaluate : ∫x cosx dx concept: Indefinite Integration - Integration by Parts. For the courses HSC Commerce, HSC Commerce (Marketing and Salesmanship)