Question

Find the roots of the following quadratic equations by factorisation `2x^2 – x + 1/8 = 0`

Answer 1

2x² – x + `1/8`

=`1/8` (16x²  - 8x + 1)

= `1/8 (16x^2  - 4x -4x + 1)`

= `1/8 (4x(4x  - 1) -1(4x - 1))`

= `1/8(4x - 1)^2`

Roots of this equation are the values for which (4x - 1)² = 0

∴ (4x - 1) = 0 or (4x - 1) = 0

⇒ x = 1/4 or x = 1/4